As transducer diameter decreases, the beam spread:

Master Ultrasonic Testing Level 2 Exam. Study with flashcards and multiple choice questions, each question has hints and explanations. Prepare confidently for your certification!

Multiple Choice

As transducer diameter decreases, the beam spread:

Explanation:
Beam spread in ultrasonic beams is set by diffraction from the transducer’s finite aperture. For a circular transducer, the far-field pattern’s first minimum occurs at an angle θ that roughly satisfies sinθ ≈ 1.22 λ / D. Here, λ is the wavelength and D is the transducer diameter. When the diameter D decreases, the ratio λ / D grows, so θ increases and the beam becomes more divergent. In practical terms, energy is spread over a larger area, which lowers lateral resolution and reduces signal strength at depth. The beam doesn’t suddenly take a perfect conical shape; it becomes more divergent overall. Therefore, as transducer diameter decreases, beam spread increases.

Beam spread in ultrasonic beams is set by diffraction from the transducer’s finite aperture. For a circular transducer, the far-field pattern’s first minimum occurs at an angle θ that roughly satisfies sinθ ≈ 1.22 λ / D. Here, λ is the wavelength and D is the transducer diameter. When the diameter D decreases, the ratio λ / D grows, so θ increases and the beam becomes more divergent. In practical terms, energy is spread over a larger area, which lowers lateral resolution and reduces signal strength at depth. The beam doesn’t suddenly take a perfect conical shape; it becomes more divergent overall. Therefore, as transducer diameter decreases, beam spread increases.

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